
Let,
Base =BC = 4k
Hypotenuse =AC = 5k
Where, k ia any positive integer
So, by Pythagoras theorem, we can find the third side of a triangle
⇒ (AB)2 + (BC)2 = (AC)2
⇒ (AB)2 + (4k)2 = (5k)2
⇒ (AB)2 + 16k2 = 25k2
⇒ (AB)2 = 25 k2 –16 k2
⇒ (AB)2 = 9 k2
⇒ AB =√9 k2
⇒ AB =±3k
But side AB can’t be negative. So, AB = 3k
Now, we have to find tan θ
We know that,
