
Let,
The side opposite to angle θ =AB = 3k
The side adjacent to angle θ =BC = 4k
where k is any positive integer
Firstly we have to find the value of AC.
So, we can find the value of AC with the help of Pythagoras theorem
⇒ (AB)2 + (BC)2 = (AC)2
⇒ (3k)2 + (4k)2 = (AC)2
⇒ (AC)2 = 9 k2+16 k2
⇒ (AC)2 = 25 k2
⇒ AC =√25 k2
⇒ AC =±5k
But side AC can’t be negative. So, AC = 5k
Now, we will find the sin θ and cos θ

Side opposite to angle θ = AB = 3k
and Hypotenuse = AC = 5k
