u = -20 cm
f = 10 cm
\(\frac 1f = \frac 1v - \frac 1u\)
\(\frac 1v = \frac 1f + \frac 1u\)
\(\frac 1v = \frac 1{10} + \frac1{(-20)}\)
\( \frac 1v = \frac 1{10} - \frac 1{20}\)
\(\frac 1v = \frac {2-1}{20}\)
\( \frac 1v = \frac 1{20}\)
\(\Rightarrow v = 20 cm\)

Nature of the image real enlarged and inverted image.