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Find the least number which when divided by 6, 15 and 18, leave remainder 5 in each case.

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Find the least number which when divided by 6, 15 and 18, leave remainder 5 in each case.

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L.C.M. of 6, 15 and 18 = 2 x 3 x 3 x 5 = 90

Therefore the required number = 90 + 5 = 95

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