Question

Find the smallest 4-digit number which is divisible by 18, 24 and 32.

Answer 1

L.C.M. of 18, 24 and 32 = 2 x 2 x 2 x 2 x 2 x 3 x 3 = 288

The smallest four-digit number = 1000

Now,

Therefore, the required number is 1000 + (288 – 136) = 1152.

Answer 2

L.C.M of 18, 24 and 32 = 2 x 2 x 2 x 2 x 2 x 3 x 3 =288

The smallest four-digit number = 1000

Now,

Therefore, the required number is 1000+(288-136)=1152.