Question

In the figure, `AC=8cm`, `/_ABC=90^(@)`. `/_BAC=60^(@)`, `/_ACB=30^(@)`. Complete the following activity to find `AB` and `BC`.

In `DeltaABC`,
By `30^(@)-60^(@)-90^(@)` triangle theorem,
`:.AB=(1)/(2)xxAC` and `BC=-AC`
`:.AB=(1)/(2)xx8` and `BC=-xx8`
`:.AB=square cm` and `BC= square cm`

Answer 1

In `DeltaABC`,
By `30^(@)-60^(@)-90^(@)` triangle theorem,
`:.AB=(1)/(2)xxAC` and `BC=(sqrt(3))/(2)AC`
`:.AB=(1)/(2)xx8` and `BC=(sqrt(3))/(2)xx8`
`:.AB=4 cm` and `BC= 4sqrt(3) cm`