Correct Answer - C
c. From ideal gas equation
`PV = RT`
`P Delta T = R Delta T`
Dividing Eq. (ii) by Eq. (i), we get
`(Delta T)/(V) = (Delta T)/(T) implies (Delta V)/(V Delta T) = (1)/(T) = delta` (given)
`:. Delta = (1)/(T)`
So the graph between `delta` and `T` will be a rectangular hyperbola.