Question

An ideal gas is initially at temperature T and volume V. Its volume is increased by `DeltaV` due to an increase in temperature `DeltaT,` pressure remaining constant. The quantity `delta=(DeltaV)/(VDeltaT)` varies with temperature as
A.
B.
C.
D.

Answer 1

Correct Answer - C
From ideal gas equation , pV= RT
or `" "pDeltaV=RDeltaT`
Dividing Eqs. (ii) by (i), we get
`(DeltaV)/(V)=(DeltaV)/(T) rArr(DeltaV)/(VDeltaT)=1/T=delta`
`therefore delta=1/T.` So, the graph between `delta` and T will be rectangular hyperbola.