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An ideal gas is initially at temperature T and volume V. Its volume is increased by `DeltaV` due to an increase in temperature `DeltaT,` pressure remaining constant. The quantity `delta=(DeltaV)/(VDeltaT)` varies with temperature as
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Correct Answer - C
As `P` = constant so `PDeltaV = nRDeltaT implies delta = (DeltaV)/(VDeltaT) = (nR)/(PV) = (1)/(T)`

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