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An ideal gas is initially at temperature T and volume V. Its volume is increased by `DeltaV` due to an increase in temperature `DeltaT,` pressure remaining constant. The quantity `delta=(DeltaV)/(VDeltaT)` varies with temperature as
A. image
B. image
C. image
D. image

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Correct Answer - C
We know that `V//T=`constant
`(V+DeltaV)/(T+DeltaT)=(V)/(T)` or `VT=TDeltaV=VT+VDeltaT`
or `TDeltaV=VDeltaT` or `(DeltaV)/(VDeltaT)=(1)/(T)`
This is representeed by graph.

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