Question

The period of oscillation of a simple pendulum in the experiment is recorded as `2.63s, 2.56s, 2.42s, 2.71s` and `2.80s` respectively. The average absolute error is
A. 0.1 s
B. 0.11 s
C. 0.01 s
D. 1.0 s

Answer 1

Correct Answer - B
Mean value `bara = (2.63 + 2.56 + 2.42 + 2.71+ 2.80)/(5)`
`" "bara = 2.624`
absolute error in various reading are
`Delta a_1 = 2.624 - 2.63 = -0.006`
`Delta a_2 = 2.624- 2.56 = 0.064`
`Delta a_3 = 2.624- 2.42= 0.204`
`Delta a_4 = 2.624 - 2.71= -0.086`
`Delta a_5= 2.624 - 2.80 = -0.176`
`bar(Deltaa) = (|Deltaa_1|+|Deltaa_2| + |Deltaa_3| + |Deltaa_4| + |Deltaa_5|)/(5) = 0.11 sec`