Question

The period of oscillation of a simple pendulum in the experiment is recorded as `2.63s, 2.56s, 2.42s, 2.71s` and `2.80s` respectively. The average absolute error is
A. 0.1s
B. 0.11s
C. 0.01s
D. 1.0s

Answer 1

Mean value `veca=(2.63+2.56+2.42+2.71+.2.80)/(5)`
`vec=2.624`
absolute error in various readings are
`Deltaa_(1)=2.624-2.63=-.006`
`Deltaa_(2)=2.624-2.56=0.64`
`Deltaa_(3)=2.624-2.42=-204`
`Deltaa_(42.624-2.71=-.086`
`Deltaa_(5)=2.624-2.80=-.176`
`overlineDeltaa=(|Deltaa_(1)|+|Deltaa_(2)|+|Deltaa_(3)|+|Deltaa_(4)|+|Deltaa_(5)|)/(5)`
`=0.11` sec