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In successive measurement, the reading of the period of oscillation of a simple pendulum were found to be 2.63s, 2.56s, 2.71s and 2.80s in an experiment. Calculate (i) mean value of the period oscillation (ii) absolute errer in each measurement (iii) mean absolute error (iv) releative error (v) percentage error and (vi) express the result in proper form.

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The mean period of oscillation of the pendulum
`T=((2.63+2.56+2.42+2.71+2.80)s)/(5)`
`=13.12/5 s`
`=2.624 s`
`=2.62 s`
As the periods are mesured to a resolution of 0.01 s, all times are to the second decimal, it is proper to put this mean period also to the second decimal.
The errors in the measurements are
`2.63 s-2.62 s=0.01 s`
`2.56 s-2.62 s=-0.06 s`
`2.42 s-2.62 s=-0.20 s`
`2.71 s-2.62 s=0.09 s`
`2.80 s-2.62 s=0.18 s`
Note that the errors have the same units as the quantity to be measured.
The arithmatic mean of all the absolute errors (for arithmetic mean, we take only the magnitudes) is
`DeltaT_("mean")=[(0.01+0.06+0.20+0.09+0.18)s]//5`
`=0.54 s//5`
`=0.11 s`
That means, the period of oscillation of the simple pendulum is `(2.62 pm 0.11) s` i.e. it lies between `(2.62+0.11)s` and `(2.62-0.11) s` or between 2.73 s and 2.51 s. As the arithmetic mean of all the absolute errors is 0.11 s, there is already an error in the tenth of a second. Hence there is no point in giving the period to a hyndredth. A more correct way will be to write
`T=2.6 pm 0.1 s`
Note that the last numeral 6 is unreliable, since it may be anything between 5 and 7. We indicate this by saying that the measurement has two significant figures. In this case, the two significant figures are 2, which is reliable and 6, which has an error associated with it. You will learn more about the significant figures in section 2.7.
For this example, the relative error or the percentage error is
`deltaa=0.1/2.6xx100=4 %`

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