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For any three vectors `veca, vecb, vecc` the value of `vecaxx(vecbxxvecc)+vecbxx(veccxxveca)+veccxx(vecaxxvecb)`, is
A. `vec0`
B. `[(veca, vecb, vecc)]veca`
C. `[(veca, vecb, vecc)]vecb`
D. `[(veca, vecb, vecc)]vecc`

1 Answer

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Best answer
Correct Answer - A
We have
`vecaxx(vecbxxvecc)+vecbxx(veccxxveca)+veccxx(vecaxxvecb)`
`={(veca.vecc)vecb(veca.vecb)vecc}+{(vecb.veca)vecc-(vecb.vecc)veca}`
`+{(vecc.vecb)veca-(vecc.veca)vecb}`
`={(veca.vecc)vecb-(veca.vecb)vecc}+{(veca.vecb)vecc-(vecb.vecc)veca}`
`+{(vecb.vecc)veca-(veca.vecc)vecb}`
`=vec0`.

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