Correct Answer - B
We have
`(vecaxxvecb)xx(vecaxxvecc)={(vecaxxvecb).vecc}veca-{(vecaxxvecb).veca}vecc`
`implies (vecaxxvecb)xx(vecaxxvecc)=[(veca, vecb, vecc)]veca-[(veca, vecb, veca)]vecc=[(veca, vecb, vecc)]=[(veca, vecb, vecc)]veca`
Similarly we have
`(vecbxxvecc)(vecbxxveca)=[(vecb, vecc, veca)]vecb` and `(veccxxveca)xx(veccxxvecb)=[(vecc, veca, vecb)]vecc`
So the given expression is equal to `[(veca, vecb,vecc)](veca+vecb+vecc)`