In an excited state of hydrogen like atom an electron has total energy of `-3.4 eV`. If the kinetic energy of the electron is E

In an excited state of hydrogen like atom an electron has total energy of `-3.4 eV`. If the kinetic energy of the electron is E and its de-Broglie wavelength is `lambda`, then
A. `E=6.8eV.lambda=6.6xx10^(-10)`m
B. `E=3.4eV,lambda=6.6xx10^(-10)`m
C. `E=3.4eV.lambda=6.6xx10^(-11)`m
D. `E=6.8eV.lambda=6.6xx10^(-11)`m

In an excited state of hydrogen like atom an electron has total energy of `-3.4 eV`. If the kinetic energy of the electron is E and its de-Broglie wav

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

Find MCQs & Mock Test

Related questions

Categories