Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
83 views
in Physics by (89.4k points)
closed by
नीचे दी गई क्षय योजना में, `gamma`- क्षयों की विकिरण आवृत्‍तियों एवं `beta`- कणों की अधिकतम गतिज ऊर्जाएं ज्ञात कीजिए।
image

1 Answer

0 votes
by (89.4k points)
selected by
 
Best answer
`gamma_(1)` के संगत ऊर्जा
`E_(1)=1.088-0=1.088KeV`
`=1.088xx1.6xx10^(-13)J`
`gamma_(1)` हेतु आवृत्‍ति `v_(1)=(E_(1))/h=(1.088xx1.6xx10^(-13))/(6.63xx10^(-34))`
`=2.63xx10^(20)Hz`
`gamma_(2)` के संगत ऊर्जा
`E_(2)=0.412-0=0.412MeV`
`=0.412xx1.6xx10^(-13)J`
`gamma_(2)` के लिए आवृत्‍ति `=v_(2)=(E_(2))/h=(0.412xx1.6xx10^(-13))/(6.63xx10^(-34))`
`=9.98xx10^(19)Hz`
`gamma_(3)` के संगत ऊर्जा
`E_(3)=1.088-0.412=0.976MeV`
`=0.676xx1.6xx10^(-13)J`
`gamma_(3)` के लिए आवृत्‍ति
`v_(3)=(E_(3))/h=(0.676xx1.6xx10^(-13))/(6.63xx10^(-34))`
`v_(3)=1.64xx10^(20)Hz`
`beta_(1)` के लिए अधिकतम गजि ऊर्जा
`K_(“max”)(beta_(1))=[m(._(79)^(198)Au)-._(80)^(198)Hg` की द्वितीय अवस्था द्रव्यमान`]xx931MeV`
`=931[197.968233-197.66760]-1.088`
`=1.371-1.088=0.283MeV`
`beta_(2)` के लिए अधिकतम गतिज ऊर्जा-
`K_(“max”)(beta_(2))=[m(._(79)^(198)Au)-Hg^(198)` की तृतीय अवस्था का द्रव्यमान`]xx931MeV`
`=931[197.968233-197.66760]-0.412`
`=0.957MeV`

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...