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A set of tuning forks is arranged in ascending order of frequency each tuning fork gives 5 beats s with the preceding one. If frequency of the firs tuning fork is 100 Hz and the last fork is 150 Hz then the number of tuning forks arranged will br
A. 9
B. 10
C. 11
D. 12

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Best answer
Correct Answer - C
Number of tuning forks arranged in series
`= ("difference in frequency")/("beat frequency") + 1`
`= (150 - 100)/(5) + 1 = (50)/(5) + 1 = 10 + 1 = 11`

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