Question

A set of tuning forks is arranged in ascending order of frequency. Each tuning fork gives 5 beats per second with the preceding one. If the frequency of the first tuning fork is 100 Hz and that of last fork is 150 Hz, then the total number of tuning forks arranged are
A. 9
B. 10
C. 11
D. 12

Answer 1

Correct Answer - C
`N = (n_(2) - n_(f))/(x) + 1`
`= (150 - 100)/(5) +1 = (50)/(5) + 1 = 10 + 1 = 11`