Correct Answer - B
In steady state current in capacitor branch is zero hence `r_(0)` can be removed
Voltage across `R_(1):` `IR_(1)=(ER_(1))/(r+R_(1)+R_(2))`
`:.` Voltage across capacitor `=(ER_(1))/(r+R_(1)+R_(2))+E_(0)`
`:.` Energy stored in capacitor `=(1)/(2)C(E_(0)+(ER_(1))/(r+R_(1)+R_(2)))^(2)`