We have y = f(x) = x sin x.
First draw the graph of `y = +-x`.
Now consider the values of f(x) for quadrant angles.
f(0) = 0
`f(pi//2) = pi//2`
`f(pi) = 0`
`f(3pi//2) = -3pi//2`
`f(2pi) = 0`
`f(5pi//2) = 5pi//2` etc.
Points `(pi//2, pi//2), (5pi//2, 5pi//2), ...` lie on the graph of y = x.
Points `(3pi//2, 3pi//2), (7pi//2, 7pi//2),...` lie on the graph of y = -x.
Further f(x) = f(-x), hence the function is even and the graph is symmetrical about the y-axis.
From the above discussion, the graph of the function is as shown in the following figure.
