Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
94 views
in Trigonometry by (95.0k points)
closed by
Draw the graph of `y = sin pisqrt(x)`.

1 Answer

0 votes
by (90.2k points)
selected by
 
Best answer
We have `y = f(x) = sin pisqrt(x)`
Clearly, the domain of the function is `[0, oo).`
`sin pi sqrt(x) = 0`
`therefore` `pi sqrt(x) = n pi, n in Z`
`therefore` `x = n^(2), n in Z`
Also `sin pi sqrt(x) gt 0`
`therefore` `pi sqrt(x) in underset(n = 1)overset(oo)uuu (2npi, (2n + 1)pi)`
`therefore` `x in underset(n = 1)overset(oo)uuu (4n^(2), (2n + 1)^(2))`
Similarly, sin `pi sqrt(x) lt 0` for `x in underset(n in z^(+))uuu ((2n + 1)^(2), (2n + 2)^(2))`
Thus, the graph of the function is as follows.
image

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...