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If \(\begin{vmatrix}a&1&1\\1&b&1\\1&1&c\end{vmatrix} =0\) then show that \(\frac {1}{1-a}+\frac{1}{1-b} +\frac{1}{1-c}=1\)

[(a, 1, 1) (1, b, 1) (1, 1, c)} = 0 

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 \(\begin{vmatrix}a&1&1\\1&b&1\\1&1&c\end{vmatrix} =0\) 

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