Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.7k views
in General by (106k points)
closed by
A steel plate 120 mm wide and 20 mm thick is bent into a circular are of radius 10 m. What is the maximum stress produced and the bending moment which can produce this stress respectively ? (Take E = 200 GPa)
1. 100 MPa, 32 kN-m
2. 200 MPa, 1.6 kN-m
3. 200 MPa, 1600 kN-m
4. 20 MPa, 160 kN-m

1 Answer

0 votes
by (106k points)
selected by
 
Best answer
Correct Answer - Option 2 : 200 MPa, 1.6 kN-m

Explanation:

Given data:

R= 10 m = 10000 mm,

E = 200GPa = 200000 N/mm2,

b = 120 mm, d or t = 20mm, y = 10 mm

Now MOI

I = (bt3)/12 = (120x203)/12 = 80000 mm4

Using Simple bending theory find the value of Maximum Stress

 \(\frac{σ }{y} = \frac{E}{R}\)

 \(\frac{σ }{10} = \frac{200000}{10000}\) ⇒ σ = 200 MPa

So Bending Moment for this Stress

 \(\frac{M}{I} = \frac{σ }{y}\)

 \(\frac{M}{80000} = \frac{200}{10}\)= 1600000

 = 1.6 x 106 N-mm = 1.6 kN-m

 Simple Bending Theroy

 \(\frac{M}{I} = \frac{σ }{y} = \frac{E}{R}\)

 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...