Correct Answer - Option 2 : 200 MPa, 1.6 kN-m
Explanation:
Given data:
R= 10 m = 10000 mm,
E = 200GPa = 200000 N/mm2,
b = 120 mm, d or t = 20mm, y = 10 mm
Now MOI
I = (bt3)/12 = (120x203)/12 = 80000 mm4
Using Simple bending theory find the value of Maximum Stress
\(\frac{σ }{y} = \frac{E}{R}\)
\(\frac{σ }{10} = \frac{200000}{10000}\) ⇒ σ = 200 MPa
So Bending Moment for this Stress
\(\frac{M}{I} = \frac{σ }{y}\)
\(\frac{M}{80000} = \frac{200}{10}\)= 1600000
= 1.6 x 106 N-mm = 1.6 kN-m
Simple Bending Theroy
\(\frac{M}{I} = \frac{σ }{y} = \frac{E}{R}\)