Correct Answer - Option 3 : – 2 ± i
Closed loop transfer function poles are nothing but roots of characteristic equation.
\(\begin{array}{l}
1 + G\left( s \right)H\left( s \right) = 0\\
1 + \frac{1}{{{{\left( {s + 2} \right)}^2}}} = 0\\
\Rightarrow {s^2} + 4s + 5 = 0\\
\Rightarrow s = - 2 \pm i
\end{array}\)