Correct Answer - Option 3 : unstable
Routh-Hurwitz stability criterion:
- Used to find whether the system is stable or unstable.
- Used to find the how many roots of the given system lies in left and right half of the s-plane.
Calculation:
Given:
Open-loop transfer function ⇒ \(G\left( s \right) = \frac{{{{10}^4}}}{{s{{\left( {s + 10} \right)}^2}}}\)
For unity feedback ⇒ H(s) = 1
Characteristic equation ⇒ 1 + G(s)H(s) = 0
⇒ \(1 + \frac{{{{10}^4}}}{{s{{\left( {s + 10} \right)}^2}}} = 0\)
⇒ s(s+10)2 + 104 = 0
⇒ s3 + 20s2 +100s + 10000 = 0
Routh Hurwitz table:
s3
|
1
|
100
|
s2
|
20
|
10000
|
s1
|
\(\frac{{20 \times 100 - 1 \times 10000}}{{20}} = - 400\)
|
|
s0
|
\(\frac{{ - 400 \times 1000 - 0}}{{ - 400}} = 10000\)
|
|
There are 2 sign change
First from 20 to -400
Second from -400 to 10000
So, two roots will lie on the right half of the s-plane.
∴ System is unstable.