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The angular frequency of the charged particle in a cyclotron is
1. inversely proportional to its mass
2. directly proportional to mass
3. directly propotional to its speed
4. inversely proportional to its speed

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Correct Answer - Option 1 : inversely proportional to its mass

The correct answer is option 1) i.e. inversely proportional to its mass

CONCEPT:

  • A cyclotron is a particle accelerator that accelerates charged particles to higher energies.
    • ​The working principle of a cyclotron is the Lorentz force.
    • The charged particle is placed at the center of the arrangement between the poles of two electromagnets.
    • The magnetic field causes the particle to trace a circular path as it experiences a Lorentz force.
    • An alternating voltage is applied across the setup, which further accelerates the particle.
  • Lorentz force is the force experienced by electrically charged particles moving in a magnetic field.
    • The magnitude of the magnetic force (F) on a charge (q) moving at a speed (v) in a magnetic field of strength B is given by​

⇒ F = qvB

EXPLANATION:

  • When a charged particle moves perpendicular to the magnetic field (θ = 90), it follows a curved path and undergoes circular motion.
  • Here, the magnetic force supplies the centripetal force which keeps the particle in a circular motion.
  • The centripetal force, 

\(⇒ F_C = \frac{mv^2}{r}\) ​

Where m is the mass of the particle, v is the velocity of the particle, and r is the radius of the circular path traced by the particle.

\(\therefore F = F_C⇒qvB = \frac{mv^2}{r}\)

\(⇒\frac{v}{r} = \frac{qB}{m}\)      ----(1)

  • Angular velocity of the body is given as, 

\(⇒ ω = \frac{v}{r} \) 

Where r = radius and ω = 2πf, where f is the frequency.

Substituting (1) in the equation for ω,

\(\Rightarrow \omega = \frac{qB}{m} = 2\pi f\)

\(\Rightarrow f =\frac{qB}{2\pi m}\)

\(\Rightarrow f \propto \frac{1}{m}\)

  • The angular frequency of the charged particle in a cyclotron is inversely proportional to its mass.

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