Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
110 views
in Physics by (56.9k points)
closed by

A stream of glass balls, moving vertically upwards with a speed u, strike a horizontal plate (of mass M) and rebound, therefrom, with the same speed. The disc can be kept floating horizontally, if the number of glass balls (each of mass m), striking it per second, equals.

(1) (2mU/Mg)

(2) (Mg/2mU)

(3) (Mg/mU)

(4) (mU/Mg)

1 Answer

+1 vote
by (54.1k points)
selected by
 
Best answer

(2) (Mg/2mU)

Let N be the required number of balls striking the plate per second. The change in momentum of each ball, upon striking the plate is

mU - (-mU) = 2mU

∴ Total change in momentum, per second, when N balls strike the ball in one second, is

(2mU) x N = 2mUN.

This rate of change of momentum equals the force exerted on the plate by the glass balls, striking it from below. It is this force that balances the weight of the horizontally floating plate. 

Hence,

2mUN = Mg

∴ N = (Mg/2mU)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...