(2) (Mg/2mU)
Let N be the required number of balls striking the plate per second. The change in momentum of each ball, upon striking the plate is
mU - (-mU) = 2mU
∴ Total change in momentum, per second, when N balls strike the ball in one second, is
(2mU) x N = 2mUN.
This rate of change of momentum equals the force exerted on the plate by the glass balls, striking it from below. It is this force that balances the weight of the horizontally floating plate.
Hence,
2mUN = Mg
∴ N = (Mg/2mU)