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A pure siliconn sample has ne = 1.3 x 1016 m-3. The material is doped with 

(a) 1019 atoms m-3 of phosporous 

(b) 2 x 1019 atoms m-3 of boron

one by one. What is ratio of resistivity of doped sample in (a) and (b) due to majority charge carriers? 

Given: 

Mobility of electrons = 0.125 m2V-1s-1, Mobility of holes = 0.0426 m2V-1s-1 .

(1) 1

(2) 2

(3) 1/2

(4) 2/3

1 Answer

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 (4) 2/3

(a) The majority charge carriers are electrons.

ne = Number of free electrons = 109 m-3; μe = 0.125 m2V-1 s-1 

\(ρ_e\) = Resistivity of material = \(\frac{1}{n_e eμ_e}\)

(b) The majority charge carriers are holes nh = Number of holes = 2 x 1019 m-3 , μn = 0.426 m2V-1s-1

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