For minimum work required to compressor is isentropic
∴ Actual work required
Wact = \(\frac{181.55}{0.75}\) = 242 kJ/kg
(a) ∴ Power required driving the compressor
= \(\overset • m\) Wact
= 2.42 kW
Extra work added in 2′ to 2 is (242 – 181.55) = 60.85 kJ/kg
∴ If CP (T2 - T'2) = 60.85
or T2 = \(\frac{60.85}{1.005}\)
= 529.25 K
∴ Availability loss due to cooling
∴ Total available energy loss = (60.85 + 65.302) kJ/kg
= 126.15 kJ/kg
∴ Power loss due to irreversibility = 1.2615 kW