Correct answer: 12

At surface BC
\(\sqrt{\frac{3}{2}} \sin r_2=\sqrt{3} \sin 30\)
\(\sqrt{\frac{3}{2}} \sin r_2=\frac{\sqrt{3}}{2}\)
\(\sin _2=\frac{1}{\sqrt{2}}\)
\(\mathrm{r}_2=45^{\circ}\)
\(\mathrm{r}_1=60^{\circ}-45^{\circ}=15^{\circ}\)
At surface AB
\(1 \sin \theta=\sqrt{\frac{3}{2}} \sin 15^{\circ}\)
\(\theta=\sin ^{-1}\left[\sqrt{\frac{3}{2}} \sin \frac{\pi}{12}\right]\)
\(\beta=12\)