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What will be the number of molecules in  10 mL water vapour at S.T.P. ?

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At S.T.P., volume of 6.022 × 1023 molecules = 22.4 L 

At S.T.P., 22400 mL water vapour contains  = 6.022 × 1023 molecules .

So, at S.T.P., 10 mL of water vapour will contain 

\( = \frac{6.022\times 10^{23}\times 10}{22400}\)

= 2.69 × 1020 molecules

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