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Find the product:

(a − 2b + 3c)(ab2 − a2b)

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(a − 2b + 3c)(ab2 − a2b) 

= a(ab− a2b) − 2b(ab− a2b) + 3c(ab− a2b)

= a2b− a3b − 2ab3 + 2a2b2 + 3ab2c − 3a2bc

= (a2b2 + 2a2b2) − a3b − 2ab3 − 3a2bc + 3ab2c

= a2b2(1 + 2) − a3b − 2ab3 − 3a2bc + 3ab2c

= 3a2b2 − a3b − 2ab3 − 3a2bc + 3ab2c

Hence, (a − 2b + 3c)(ab2 − a2b) = 3a2b2 − a3b − 2ab3 − 3a2bc + 3ab2c.

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