Answer is: 2
\(\lim\limits _{x \rightarrow 0} \frac{\frac{\tan (\tan x)-\tan x}{\tan ^{3} x} \frac{\tan ^{3} x}{x^{3}}+\frac{\tan x-\sin x}{x^{3}}+\frac{\sin x-\sin (\sin x)}{\sin ^{3} x} \frac{\sin ^{3} x}{x^{3}}}{\frac{\tan x-\sin x}{x^{3}}}\)
\( =\frac{\frac{1}{3}+\frac{1}{2}+\frac{1}{6}}{\frac{1}{2}}=2\)