If ê1=unit vector along incident ray,ê2=unit vector along reϐlected ray & n̑=unit vector along normal, then vector form of laws of Reflection is ê2=e1-2(ê1.n̑) n̑

n̑= (2i+2j+k)/3
ê2=? e1=-i
Using vector form of laws of Reflection ê2=e1-2(ê1.n̑) n̑
ê2= -i-2(-2/3) (2i+2j+k)/3 = -i+4 (2i+2j+k)/9= (-i+8j+4k)/9