For Bivariate, both x and y variables having common differences. So use step deviation method:



Regression equation of x on y : (x – x̄) = bxy (y – ȳ)
x – 25 = 0.256 (y – 19.8)
= 0.256y – 0.256 × 19.8x
=0.256y – 5.0688 + 25
∴ x = 0.256y + 19.9312
Regression equation of y on x = (y – ȳ) = bxy (x – x̄)
y – 19.8 = 0.667(x – 25)
∴ = 0.6667x – 0.667 × 25
y = 0.6667x – 16.675 + 19.8
∴ y = 0.667x + 3.125
