2√3 x2 – 5x + √3 = 0
Compare given equation with the general form of quadratic equation, which is ax2 + bx + c = 0
a = 2√3, b = – 5 , c = √3
Find Discriminant:
D = b2 – 4ac
= (– 5)2 – 4 x 2√3 x √3
= 25 – 24
= 1 > 0
Roots of equation are real.
Find roots:

Roots are:
x = √3/2 and x = 1/√3