Atoms X and Y form bcc crystalline structure. Atom X is present at the corners of the cube Atom Y is present at the centre of the cube.
No of atoms of X in the unit cell = \(\frac{N_c}{8}\,=\frac{8}{8}\) = 1
No of atoms of Y in the unit cell = \(\frac{N_b}{1}\,=\frac{1}{1}\) = 1
Ratio of atoms X : Y = 1 : 1
Hence formula of the compound = XY