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The roots of the equation x2 + 6x – 4 = 0 are α, β. Find the quadratic equation whose roots are

(i) α2 and β2

(ii) 2/α and 2/β

(iii) α2β and β2α

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Best answer

If the roots are given, the quadratic equation is x2 – (sum of the roots) x + product the roots = 0.

For the given equation.

x2 + 6x – 4 = 0

α + β = -6

αβ = -4

(i) α2 + β2 = (α + β)2 – 2αβ

= (-6)2 – 2(-4) = 36 + 8 = 44

α2β2 = (αβ)2 = (-4)2 = 16

∴ The required equation is x2 – 44x – 16 = 0.

(ii) 2/α and 2/β

(iii) α2β and β2α

α2 β + β2 α = αβ(α + β)

= -4(-6) = 24

α2 β x β2 α = α3 β3 = (αβ)3 = (-4)3 = -64

∴ The required equation = x2 – 24x – 64 – 0.

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