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If the distance from the vertex to the centroid of an equilateral triangle is 6 cm, then what is the area of the triangle?

(a) 24 cm2 

(b) 27√3 cm2 

(c) 12 cm2 

(d) 12√3 cm2

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(b) 27√3 cm2 

Here OA = 6 cm ∴ OD =\(\frac{OA}{2}\) = 3 cm

AD = 6 cm + 3 cm = 9 cm 

Let each side of ΔABC be x cm. 

From right angled ΔADB,

AB2 - BD2 = AD2

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