The value of \(cos(\frac{5\pi}4)\) is \(\frac{-1}{\sqrt2}\)
Now,
∴ The question becomes \(cos^{-1}(\frac{-1}{\sqrt2})\)
Let \(cos^{-1}(\frac{-1}{\sqrt2})\) = y

The range of principal value of cos–1 is [0,π] and cos\((\frac{3\pi}4)=\frac{-1}{\sqrt2}\)
Therefore, the value of cos–1(cos\((\frac{5\pi}4)\)) is \(\frac{3\pi}4.\)